The electric potential at a point in free spa | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The electric potential $V$ due to a point charge $Q$ at a distance $r$ is given by $V = \frac{1}{4 \pi \varepsilon_0} \cdot \frac{Q}{r}$.Given $V

Vedclass · Accepted Answer

$4\pi \varepsilon_0 Q 	imes 10^{22} \, V/m$

Vedclass · Answer

(C) The electric potential $V$ due to a point charge $Q$ at a distance $r$ is given by $V = \frac{1}{4 \pi \varepsilon_0} \cdot \frac{Q}{r}$.Given $V = Q 	imes 10^{11} \, V$,we have $\frac{1}{4 \pi \varepsilon_0} \cdot \frac{Q}{r} = Q 	imes 10^{11}$.This simplifies to $\frac{1}{r} = 4 \pi \varepsilon_0 	imes 10^{11}$.The electric field $E$ at that point is given by $E = \frac{1}{4 \pi \varepsilon_0} \cdot \frac{Q}{r^2} = \left( \frac{1}{4 \pi \varepsilon_0} \cdot \frac{Q}{r} ight) \cdot \frac{1}{r}$.Substituting the values,$E = (Q 	imes 10^{11}) 	imes (4 \pi \varepsilon_0 	imes 10^{11})$.Therefore,$E = 4 \pi \varepsilon_0 Q 	imes 10^{22} \, V/m$.

The electric potential at a point in free space due to charge $Q$ coulomb is $V = Q \times 10^{11} \, V$. The electric field at that point is:

Similar Questions

Obtain the relation between electric field and electric potential.

The potential $\phi(x, y)$ of an electrostatic field $\vec{E} = a(y \hat{i} + x \hat{j})$ is [where $a$ is a constant and $\hat{i}$ and $\hat{j}$ are unit vectors along $X$ and $Y$ axes].

The figure shows the electric potential $V$ as a function of distance through five regions on the $x$-axis. Which of the following is true for the electric field $E$ in these regions?

The potential difference between two points $A(2, 1, 0) \ m$ and $B(0, 2, 4) \ m$ in an electric field $\vec{E} = (x \hat{i} - 2y \hat{j} + z \hat{k}) \ Vm^{-1}$ is: (in $V$)

The electric potential for an electric field directed parallel to $X$-axis is shown in the figure. Choose the correct plot of electric field strength.

Vedclass Test Series

Exam Paper Generator

Online Exam Module